Question

A soma de 2^24 e 16^1/2 - 4^0,5 é:

Answer 1

${2}^{24} + {16}^{ \frac{1}{2} } - {4}^{0.5}$


${2}^{24} + {16}^{ \frac{1}{2} } - {4}^{ \frac{1}{2} }$


${2}^{24} + \sqrt{16} - \sqrt{4}$


${2}^{24} + 4 - 2$


${2}^{24} = 16777216$


$16777216 + 2 = 16777218$