Question

a soma das raízes da função quadrática y=x²-5x+6

Answer 1

Resposta:

2+3 = 5

Explicação passo-a-passo:

X²-5x+6 = 0

a = 1   b = (-5)   c = 6

Δ= (-5)² - 4*1*6

Δ= 25 - 24 = 1

√Δ = 1

x1 = (5 + 1)/2 = 3

x2 = (5 - 1)/2 = 2

Portanto a soma das raízes é (3+2=) 5

Answer 2

Aplicando Bhaskara:

$\Delta=b^2-4.a.c\\\\\Delta=(-5)^2-4.1.6\\\\\Delta=25-24\\\\\Delta=1\\\\\\x=\frac{-b\pm\sqrt{\Delta}}{2a}\\\\\\x'=\frac{5+\sqrt{1}}{2.1}=\frac{5+1}{2}=3\\\\x''=\frac{5-\sqrt{1}}{2.1}=\frac{5-1}{2}=2\\\\\\Somando-se\;as\;raizes:\\x'+x''=3+2\\\\x'+x''=5$