Question

a soma das raizes da equação quadrática 3x ^2- 9x + 5

Answer 1

Resposta:

3x² + 9x -120 = 0

a = 3

b = 9

c = -120

Δ = b² - 4ac

Δ = 9² - 4·3·(-120)

Δ = 81 + 1440

Δ = 1521

x' = (C\frac{-9 + 39}{2 . 3}

2.3

−9+39

)

x' = \frac{30}{6}

6

30

x' = 5

x'' = \frac{-9-39}{2 . 3}

2.3

−9−39

x'' = \frac{-48}{6}

6

−48

x'' = -8

S = {5, -8}