Question

A solução do limite lim (x→25 (x^2-25)/(x-5))

Answer 1

Olá!

Vamos resolver o limite por fatoração:

$\lim_{x \to 25} \frac{x^2-25}{x-5}$

$\lim_{x \to 25} \frac{(x+5)*(\diagup\!\!\!\!\!x-\diagup\!\!\!\!\!5)}{(\diagup\!\!\!\!\!x-\diagup\!\!\!\!\!5)}$

$\lim_{x \to 25} = x+5 \to \lim_{x \to 25} = 25+5\to \boxed{\boxed{\lim_{x \to 25} = 30}}\end{array}}\qquad\checkmark$

Answer 2

x²-25 =(x+5)*(x-5)

Lim  (x²-25)/(x-5)
x-->25

Lim (x+5)(x-5)/(x-5)
x-->25

Lim (x+5)  =25+5=30
x-->25