Question

A solução da equação (n+3)!-4.(n+1)!/(n+2)!=4

Answer 1

Resposta:

[(n+3)!-4.(n+1)!]/(n+2)!=4

[(n+3)(n+2)(n+1)!-4.(n+1)!]/(n+2)(n+1)!=4

[(n+3)(n+2)-4]/(n+2)=4

(n+3)*(n+2)-4=4n+8

n²+2n+3n+6-4=4n+8

n²+n-6=0

n'=[-1+√(1+24)]/2=(-1+5)/2=2

n'=[-1-√(1+24)]/2=(-1-5)/2=-3

n=2  ou n=-3