Question

A soluçao da equaçao log10[3-2log10(x+1)] = 0 é

Answer 1

Explicação passo-a-passo:

$\sf log_{10}~[3-2\cdot log_{10}~(x+1)]=0$

$\sf 3-2\cdot log_{10}~(x+1)=10^0$

$\sf 3-2\cdot log_{10}~(x+1)=1$

$\sf 2\cdot log_{10}~(x+1)=3-1$

$\sf 2\cdot log_{10}~(x+1)=2$

$\sf log_{10}~(x+1)=\dfrac{2}{2}$

$\sf log_{10}~(x+1)=1$

$\sf x+1=10^1$

$\sf x+1=10$

$\sf x=10-1$

$\boxed{\sf x=9}$

Letra A