Question

A solução da equação é?

Answer 1

$\large\boxed{\begin{array}{l}\sf\begin{vmatrix}\sf2&\sf1&\sf-2\\\sf3&\sf-1&\sf0\\\sf4&\sf1&\sf-3\end{vmatrix}=2\cdot(3-0)-1\cdot(-9-0)-2\cdot(3+4)\\\sf=6+9-14=1\\\sf 2x-\begin{vmatrix}\sf2&\sf1&\sf-2\\\sf3&\sf-1&\sf0\\\sf4&\sf1&\sf-3\end{vmatrix}=0\\\\\sf 2x-1=0\\\sf 2x=1\\\sf x=\dfrac{1}{2}\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~C}}}}\end{array}}$