Question

a solução da equação 4.(2×-3)=5 .(×+3)​

Answer 1

$\boxed{\begin{array}{l}\sf 4\cdot(2x-3)=5\cdot(x+3)\\\sf 8x-12=5x+15\\\sf 8x-5x=15+12\\\sf3x=27\\\sf x=\dfrac{27}{3}\\\sf x=9\\\huge\boxed{\boxed{\boxed{\boxed{\sf\maltese~alternativa~d}}}} \end{array}}$