Question

a seguir , resolva as potencias e expresse o resultado encontrado na forma fracionária​

Answer 1

Explicação passo-a-passo:

$a) \: \: 3 {}^{ - 2} \times 5 {}^{2} = ( \frac{1}{3} ) {}^{2} \times 25 = \frac{1}{9} \times 25 = \frac{25}{9}$

$c)( \frac{1}{4} ) {}^{3} = \frac{1}{4} \times \frac{1}{4} \times \frac{1}{4} = \frac{1 \times 1 \times 1}{4 \times 4 \times 4} = \frac{1}{6}$

$b)2 {}^{10} \times 2 {}^{8} \div 2 {}^{6} = 2 {}^{10 + 8} \div 2 {}^{6} = 2 {}^{18} \div 2 {}^{6} = 2 {}^{18 - 6} = 2 {}^{12}$