Question

a reta normal a curva y = x³ - 2 no ponto p ( 1; -1)

Answer 1

Equação da reta normal de coeficiente angular $\mathsf{f'(x_{0})}$ e ponto

$\mathsf{P(x_{0},y_{0})}$

$\boxed{\boxed{\boxed{\boxed{\mathsf{y=y_{0}-\dfrac{1}{f'(x_{0})}(x-x_{0})}}}}}$

$\dotfill$

$\mathsf{f(x)=x^3-2}\\\mathsf{f'(x)=3x^2}\\\mathsf{f'(1)=3.1^2=3}$

$\boxed{\boxed{\boxed{\boxed{\mathsf{y=-1-\dfrac{1}{3}(x-1)}}}}}$