Question

a) Resolva as seguintes equações literais
II. (x + a)(x - b) = (a + 4b)x - ab​

Answer 1

(x+a)(x-b)=(a+4b)x-ab

x²+xb+ax+ab=ax+4bx-ab

x²+xb+ax+ab-ax-4bx+ab

x²-3xb+2ab

   S={x²-3xb+2ab}

Espero ter ajudado

Answer 2

Resposta:

(x + a)(x - b) = (a + 4b)x - ab

x²-xb-ax=ax-4bx-ab

x²-2ax+3bx + ab=0

x²-x*(2a-3b) +ab=0

x'= [(2a-3b) +√((2a-3b)²-4ab)]/2 =[2a-3b+√(4a²-12ab+9b²-4ab)]/2

x'= [(2a-3b) +√((2a-3b)²-4ab)]/2 =[2a-3b+√(4a²-16ab+9b)]/2

x''= [(2a-3b) -√((2a-3b)²-4ab)]/2 =[2a-3b-√(4a²-16ab+9b)]/2