Question

a razao entre as massas de aluminio e do oxigenio na substancia oxido de aluminio e igual a 7/8 calcule as massas dde aluminio e de oxigenio necessarias para formas 51g de oxido de alimunio

Answer 1

Chamando de $m_a$ a massa do alumínio e de $m_o$ a massa do oxigênio, temos:


$\dfrac{m_a}{m_o}=\dfrac{7}{8}\Longrightarrow8m_a=7m_o\Longrightarrow m_o=\dfrac{8m_a}{7}\\\\\\ m_a+m_o=51\Longrightarrow m_a+\dfrac{8m_a}{7}=51\Longrightarrow 7m_a+8m_a=357\\\\ \Longrightarrow 15m_a=357\Longrightarrow m_a=\dfrac{357}{15}\Longrightarrow\boxed{m_a=23,8\;g}\\\\\\ m_a+m_o=51\Longrightarrow 23,8+m_o=51\Longrightarrow \boxed{m_o=27,2\;g}$