Question

A probabilidade de, sortear-se um número ao acaso , o evento ser múltiplo de 2
de 1 a 30

Answer 1

Resposta:

2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30

Answer 2

A=(2,4,6,8,10,12,14,16,18,20,22,24,26,28)

N(A)=14

N(U) =30

P(A)=?

$\mathsf{P(A)=\dfrac{N(A)}{N(U)}}\\\mathsf{P(A)=\dfrac{14\div2}{30\div2}}$

$\huge\boxed{\boxed{\boxed{\mathsf{P(A)=\dfrac{7}{15}}}}}$