Question

A pergunta ta na imagem abaixo :

Answer 1

$a=(\frac{1}{4})^{-2}+(\frac{1}{3})^{-2}\\\\ a=(4^{-1})^{-2}+({3}^{-1})^{-2}\\\\ a=(4)^2+(3)^2=16+9\\\\ a=25\\\\ b=\frac{2(\frac{1}{3})^{-1}-2^2}{(\frac{1}{2})^{-2}}\\\\ b=\frac{2(3^{-1})^{-1}-2^{2}}{(2^{-1})^{-2}}\\\\ b=\frac{2.3^{1}-2^2}{2^{2}}\\\\ b=\frac{2.3-4}{4}\\\\ b=\frac{6-4}{4}\\\\ b=\frac{2}{4}\\\\ b=\frac{1}{2}\\\\ Calcular \ a^b\\\\ a^b=25^{\frac{1}{2}}=(5^2)^{\frac{1}{2}}=5^{2.\frac{1}{2}}=5^1=5$