Question

A)n!/(n-1)!
B)(2n+2)!/(2n+1)!
C)(n+2)!/(n-1)!​

Answer 1

A)n!/(n-1)!
n(n-1)!/(n-1)! = n

B)(2n+2)!/(2n+1)!
(2n+2)(2n+1)!/(2n+1)! = (2n+2)

C)(n+2)!/(n-1)!
(n+2)(n+1)n(n-1)!/(n-1)! = n(n+1)(n+2)

Answer 2

a)

n!/(n-1)!
=n(n-1)!/(n-1)!

simplifica se o (n-1)! e fica:

=n


b)

(2n+2)!/(2n+1)!
=(2n+2)(2n+1)!/(2n+1)!

simplifica se o (2n+1)! e fica:

=2n+2


c)

(n+2)!(n-1)!
=(n+2)(n+1)n(n-1)!/(n-1)!

simplifica se o (n-1)! e teremos:

=(n+2)(n+1)n
=(n+2)(n²+n)
=n³+n²+2n²+2n
=n³+3n²+2n



bons estudos!!!!!!
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