Matemática, perguntado por barbaraferreira6440, 1 ano atrás

a-) MMC e MDC de (36,34,28):

b-)MMC e MDC de (90,36,24)

Soluções para a tarefa

Respondido por helitonsilva590
0
Vamos lá

A)

MMC

36, 34, 28 | 2

18, 17, 14 | 2

9, 17, 7 | 3

3, 17, 7 | 3

1, 17, 7 | 7

1, 17, 1 | 17

1, 1, 1

2² • 3³ • 7 • 17 = 4. 284

MDC

36, 34, 28 | 2

18, 17, 24 | 1

1, 1, 1

2 • 1 = 2

B )

MMC

90, 36, 24 | 2

45, 18, 12 | 2

45, 9, 6 | 2

45, 9, 3 | 3

15, 3, 1 | 3

5, 1, 1 | 5

1, 1, 1

2³ • 3³ • 5 = 360

MDC

90, 36, 24 | 2

45, 18, 12 | 3

15, 6, 4 | 1

1, 1, 1

2 • 3 • 1 = 6
Respondido por 76dubsbr
0

36,28,34|2

18,14,17|2

9,7,17| 3

3,7,17 |3

1,7,17 |7

1, 1,17|17

1, 1, 1|

MMC=4 284


100,54|2

50,27|2

25,27 |3

25,9 |3

25,3 |3

25,1 |5

5,1|5

1,1

MMC(100,54)= 2700


24,36,90| 2

12,18,45|2

6,9,45|2

3,9,45|3

1,3,15|3

1,1,5|5

1,1,1

MMC(24,36,90)=360


100,25,50|2

50,25,25|2

25,25,25|5

5,5,5|5

1,1,1,

MMC(100,25,50)=10

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