Matemática, perguntado por anabeatrizvictor146, 7 meses atrás

a) MMC {15, 12) =<br />b) MMC (14, 6) =<br />c) MMC {7, 10) =<br />d) MMC (25, 40) =​

Soluções para a tarefa

Respondido por marmon
0

Resposta:

Explicação passo-a-passo:

a) MMC {15, 12) =

\begin{array}{rr|c|c} &amp; &amp;  MMC &amp; MDC \\15, &amp; 12 &amp; 2\\ 15, &amp; 6 &amp; 2\\ 15, &amp; 3 &amp; 3 &amp; 3\\ 5, &amp; 1 &amp; 5\\ 1, &amp; 1\\ \end{array}\\ MMC\,\,\ 2^2 \cdot 3 \cdot 5 = 60\\ MDC\,\,\  3 = 3

b) MMC (14, 6) =

\begin{array}{rr|c|c} &amp; &amp;  MMC &amp; MDC \\14, &amp; 6 &amp; 2 &amp; 2\\ 7, &amp; 3 &amp; 3\\ 7, &amp; 1 &amp; 7\\ 1, &amp; 1\\ \end{array}\\ MMC\,\,\ 2 \cdot 3 \cdot 7 = 42\\ MDC\,\,\  2 = 2

c) MMC {7, 10) =

\begin{array}{rr|c} &amp; &amp;  MMC\\7, &amp; 10 &amp; 2\\ 7, &amp; 5 &amp; 5\\ 7, &amp; 1 &amp; 7\\ 1, &amp; 1\\ \end{array}\\ MMC\,\,\ 2 \cdot 5 \cdot 7 = 70

d) MMC (25, 40) =​

\begin{array}{rr|c|c} &amp; &amp;  MMC &amp; MDC \\25, &amp; 40 &amp; 2\\ 25, &amp; 20 &amp; 2\\ 25, &amp; 10 &amp; 2\\ 25, &amp; 5 &amp; 5 &amp; 5\\ 5, &amp; 1 &amp; 5\\ 1, &amp; 1\\ \end{array}\\ MMC\,\,\ 2^3 \cdot 5^2 = 200\\ MDC\,\,\  5 = 5

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