Question

a metade do numero 2^11 + 4^8 e quanto?????

resposta em fraçao ex: 2^9+4^8

Answer 1

2^11 + (2²)^8 = 2^11 + 2^16  = 2^11(1 + 2^5) = 2048(1 + 32) = 

= 2048 * 33 = 67584

Metade: 

(1/2) * 2048 * 33 = 1024 * 33 = 2^10 * 33

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24/02/2016 
Sepauto - SSRC
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Answer 2

A metade de $2^{11} + 4^8$ é:  $\frac{2^{11} + 4^8}{2}$

Então:

$\frac{2^{11} + 4^8}{2} = \frac{2^{11}+2^{16}}{2}= \ \ \ \ \ \ \ \ \ \ (Obs.: 4^8=(2^2)^8=2^{16}) \\\\ = \frac{2.2^{10}+2.2^{15}}{2}=2^{10}+2^{15}$

Ou ainda:
$2^{10}+2^{15} = 2^{10}+2^5.2^{10}= 2^{10}+32.2^{10}=33.2^{10}$