Question

A maior raiz da equação x² -6x +8= 0 vale

Answer 1

OI!!

 X² - 6x +8 = 0
A =1  B= -6 C=8

 usando báskara
 $\frac{6 \sqrt{36-4*1*8} }{2*1}$
 $\frac{6 \sqrt{4} }{2}$
$\frac{6+-2}{2}$
x'=$\frac{8}{2} =4$
X"=$\frac{4}{2} =2$

 Maior raiz = 4

:)

Answer 2

$x^{2} -6x +8= 0\\\\a=1;b=-6;c=8\\\\\\ \Delta = b^{2} -4ac\to \Delta = (-6)^{2} -4*1*8\to \Delta = 36-32\to \Delta =4\\ \\\\x= \frac{-b+- \sqrt{\Delta} }{2a} \to x= \frac{-(-6)+- \sqrt{4} }{2*1} \to x= \frac{6+- 2 }{2} \to \\\\\\ x'= \frac{6+ 2 }{2} \to x'= \frac{8 }{2} \to x'=4\\\\\\x''= \frac{6- 2 }{2} \to x''= \frac{4 }{2} \tox''=2\\\\\\\\S=(2,4)$




R.: A maior raiz da equação $x^{2} -6x +8= 0$ vale 4.