Question

a) log6 + log(x+2) = log48

b) log (x+3)+log4= log60

Answer 1

Utilizando a propriedade: log (a . b) = log a + log b

$a)\\log6+log(x+2)=log48\\\\log6.(x+2)=log48\\\\log(6x+12)=log48\\\\6x+12=48\\\\6x=36\\\\x=\frac{36}{6}\\\\x=6$

$log(x+3)+log4=log60\\\\log(x+3).4=log60\\\\log(4x+12)=log60\\\\4x+12=60\\\\4x=48\\\\x=\frac{48}{4}\\\\x=12$