Question

a) log₅ (x²-6x+8) = log₅ (2x-1)

Answer 1

x² - 6x + 8 = 2x - 1

x² - 6x + 8 - 2x + 1 = 0

x² - 8x + 9 = 0

x² - 8x = -9

x² - 8x + 16 = -9 + 16

(x - 4)² = √7

x - 4 = ± √7

x = 4 ± √7

x1 = 4 + √7

x2 = 4 - √7