Question

a) log2 64
b) log: 27
c) logs 625
d) log4 32
e) log25 5
f) log2 3764
g) log 16 32
h) log: 81
i) log10000​

Answer 1

Resposta:

Vamos lá

1) Calcule o valor dos seguintes logaritmos:

a) log16(64) = log(64)/log(16) = log(2^6)/log(2^4) = 6/4 = 3/2

b) log625(√5) = log(5)/2log(625) = log(5)/2*log(5^4) = 1/8

c) log5(0.000064) = log5(5^-6) = -6

d) log49(³√7) = log(7)/3log(49) = log(7)/3log(7^2) = 1/6

e) log⁵√2(128) = log(2^7)/log(2)/5 = 35

f) log9(3√3) = log(3)/2log(3) + log(3)/4log(3) = 1/2 + 1/4 = 3/4