Question

A) log 81
3

B)log 32
6

C) log 0,2
25

D) log 4
√8
me ajudem por favor com o calculo?​

Answer 1

Resposta:

A) log₃ 81 = log₃ 3⁴=4 * log₃ 3

=4*1=4

B)log₆ 32 = log 32 -log 6

=log 2⁵ -log 2*3

=5*log 2 -log 2- log 3

=4 *log 2 -log 3

C)log₂₅ 0,2  = log 0,2/log 25 =

=log (2/10) / log5²

=[log 2 -log 10]/ log 5²

=[log 2 -log 10]/2* log 5

=[log 2 -log 10]/[2*log 10/2]

=[log 2 -log 10]/[2*log 10 -2 log 2]

= -[log 10 -log 2]/[2*log 10 -2 log 2]

=-1/2

D)

$log_{\sqrt{8} } 4 = \frac{log 4}{log \sqrt{8} }$

=log 2² / log 2^(3/2)

=[2* log 2]/[(3/2)*log 2]

=2/(3/2) =4/3