Question

A) ( J+9) (J- 9)=

B) (K- 1) (K+1)=

C) ( T- 8) (T+ 8)=​

Answer 1

a) (J + 9) . (J - 9) = J² - 9J + 9J - 81 = J² - 81

b) (K - 1) . (K + 1) = K² + K - K - 1 = K² - 1

c) (T - 8) . (T + 8) = T² + 8T - 8T - 64 = T² - 64

Answer 2

Resposta:

$a)=J^2-81\\\\\\b)=K^2-1\\\\\\c)=T^2-64$

$\mathrm{Aplicar\:a\:regra\:da\:diferenca\:de\:quadrados:\:}\left(a+b\right)\left(a-b\right)=a^2-b^2\\\\a=J,\:b=9\\\\=J^2-9^2\\\\9^2=81\\\\=J^2-81$

$\mathrm{Aplicar\:a\:regra\:da\:diferenca\:de\:quadrados:\:}\left(a-b\right)\left(a+b\right)=a^2-b^2\\\\a=K,\:b=1\\\\=K^2-1^2\\\\\mathrm{Aplicar\:a\:regra}\:1^a=1\\\\1^2=1\\\\=K^2-1$

$\mathrm{Aplicar\:a\:regra\:da\:diferenca\:de\:quadrados:\:}\left(a-b\right)\left(a+b\right)=a^2-b^2\\\\a=T,\:b=8\\\\=T^2-8^2\\\\8^2=64\\\\=T^2-64$