Question

A integral raiz de 2 ate 0, integral 3y ate 0, integral 8 - x² -y² ate x² + 3y², dz, dx, dy vale:

Answer 1

Resposta:

√2 ate 0∫ , 3y ate 0∫,  -y² até x²∫ 8 - x² , dz, dx, dy

√2 ate 0∫ , 3y ate 0∫,  -y² até x²[8z - x²z],  dx, dy

√2 ate 0∫ , 3y ate 0∫[8x² - x⁴+8y²-x²y²],  dx, dy

√2 ate 0∫ , 3y ate 0[8x³/3 - x⁵/5+8xy²-x³y²/3],   dy

√2 ate 0∫[-72y³+243y⁵/5-24y³+27y⁵/3],   dy

√2 ate 0[-72y⁴/4+243y⁶/30-24y⁴/4+27y⁶/18]

√2 ate 0[-18y⁴/4+8,1y⁶-6y⁴+3y⁶/2]

-[-18(√2 )⁴/4+8,1(√2 )⁶-6(√2 )⁴+3(√2 )⁶/2]

18(√2 )⁴/4-8,1(√2 )⁶+6(√2 )⁴-3(√2 )⁶/2

=72-8,1*8 +24-12 =19,2