Question

a integral de 2X³-3X²+8X-7 dx

Answer 1

$\int 2x^3-3x^2+8x-7 \ dx= \\ \\ \int 2x^3 \ dx - \int 3x^2 \ dx + \int 8x \ dx - \int 7 \ dx=\\ \\ 2\int x^3-3 \int x^2 +8 \int x -7 \int dx=\\ \\ 2.\frac{x^4}{4}-3\frac{x^3}{3}+8.\frac{x^2}{2}-7x+C=\\ \\ \boxed{\frac{x^4}{2}-x^3+4x^2-7x+C}$