a geratriz de um cone equilátero mede 4 cm. Determine a área total, a altura e o raio do Cone
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g = 2r
4 = 2r
2r = 4
r = 4 / 2
r = 2
( g ) 2 = ( h ) 2 + (r ) 2
( 4 ) 2 = ( h ) 2 + ( 2 ) 2
16 = (h ) 2 + 4
( h ) 2 = 16 - 4
( h ) 2 = 12
h = √12
h = 2√3
Att = ( g + r ) * pi
Att = ( 4 + 2 ) * pi
Att = 6 pi
Att = 6 * 3,14
Att = 18, 84 cm 2
4 = 2r
2r = 4
r = 4 / 2
r = 2
( g ) 2 = ( h ) 2 + (r ) 2
( 4 ) 2 = ( h ) 2 + ( 2 ) 2
16 = (h ) 2 + 4
( h ) 2 = 16 - 4
( h ) 2 = 12
h = √12
h = 2√3
Att = ( g + r ) * pi
Att = ( 4 + 2 ) * pi
Att = 6 pi
Att = 6 * 3,14
Att = 18, 84 cm 2
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