A função que representa a reta baixo é
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Boa tarde Vinicius!
Solução!
![A(2,1)\\\\
B(0,-2)\\\\\\\
Coeficiente~~angular~~da~~reta!\\\\\\\
m= \dfrac{yB-yA}{xB-xA} \\\\\\\
m= \dfrac{-2-1}{0-2} \\\\\\\
m= \dfrac{-3}{-2} \\\\\\\
m= \dfrac{3}{2} \\\\\\\](https://tex.z-dn.net/?f=A%282%2C1%29%5C%5C%5C%5C%0AB%280%2C-2%29%5C%5C%5C%5C%5C%5C%5C%0ACoeficiente%7E%7Eangular%7E%7Eda%7E%7Ereta%21%5C%5C%5C%5C%5C%5C%5C%0Am%3D+%5Cdfrac%7ByB-yA%7D%7BxB-xA%7D+%5C%5C%5C%5C%5C%5C%5C%0A%0Am%3D+%5Cdfrac%7B-2-1%7D%7B0-2%7D+%5C%5C%5C%5C%5C%5C%5C%0Am%3D+%5Cdfrac%7B-3%7D%7B-2%7D+%5C%5C%5C%5C%5C%5C%5C%0Am%3D+%5Cdfrac%7B3%7D%7B2%7D+%5C%5C%5C%5C%5C%5C%5C%0A%0A%0A "A(2,1)\\\\
B(0,-2)\\\\\\\
Coeficiente~~angular~~da~~reta!\\\\\\\
m= \dfrac{yB-yA}{xB-xA} \\\\\\\
m= \dfrac{-2-1}{0-2} \\\\\\\
m= \dfrac{-3}{-2} \\\\\\\
m= \dfrac{3}{2} \\\\\\\")
Equação da reta!
Boa tarde!
Bons estudos!
Solução!
Equação da reta!
Boa tarde!
Bons estudos!
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