Question

A forma simplificada da razão entre os polinomios:

Answer 1

Resposta:

x³ - 8y³

= (x-y) (x² + 2xy + 4y²)

= (x-y) (x+2y)²

x²- 4xy + 4y²

= (x - 2y)²

Espero ter ajudado, qualquer dúvida me chame nos comentários.

Answer 2

Oie, Td Bom?!

$= \frac{x {}^{3} - 8y {}^{3} }{x {}^{2} - 4xy + 4y {}^{2} }$

$= \frac{x {}^{3} - 2 {}^{ 3}y {}^{ 3} }{x {}^{2} - 4xy + 4y {}^{2} }$

$= \frac{x {}^{3} - (2y) {}^{3} }{x {}^{2} - 4xy + 4y {}^{2} }$

$= \frac{(x - 2y) \: . \: (x {}^{2} + x \: . \: 2y + (2y) {}^{2}) }{x {}^{2} - 4xy + 4y {}^{2} }$

$= \frac{(x - 2y) \: . \: (x {}^{2} + 2xy + 4y {}^{2}) }{x {}^{2} - 4xy + 4y {}^{2} }$

$= \frac{(x - 2y) \: . \: (x {}^{2} + 2xy + 4y {}^{2} ) }{x {}^{2} - 2 \: . \: x \: . \: 2y + 2 {}^{2}y {}^{2} }$

$= \frac{(x - 2y) \: . \: (x {}^{2} + 2xy + 4y {}^{2} )}{x {}^{2} - 2 \: . \: x \: . \: 2y + (2y) {}^{2} }$

$= \frac{(x - 2y) \: . \: (x {}^{2} + 2xy + 4y {}^{2}) }{(x - 2y) {}^{2} }$

$= \frac{x {}^{2} + 2xy + 4y {}^{2} }{x - 2y}$

Att. Makaveli1996