a expressao f=9c/5+32 relacionada a temperatura na escala Fahrenheit em função da temperatura c, da dada em graus Celsius.joana viu na telejornal que na Inglaterra os termômetros marcaram 50 graus Fahrenheit.qual é o valor dessa temperatura na escala célsius?
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![\dfrac{\ºC}{5}= \dfrac{\ºF-32}{9}\\\\\\\ \ºF=50\º \\\\\\\ \dfrac{\ºC}{5}= \dfrac{50-32}{9}\\\\\\\ \dfrac{\ºC}{5}= \dfrac{18}{9}\\\\\\\
\dfrac{\ºC}{5}= 2\\\\\\
\ºC=10\º\\\\\\\
\boxed{Resposta:Temperatura=10\ºC}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5C%C2%BAC%7D%7B5%7D%3D+%5Cdfrac%7B%5C%C2%BAF-32%7D%7B9%7D%5C%5C%5C%5C%5C%5C%5C+%5C%C2%BAF%3D50%5C%C2%BA+%5C%5C%5C%5C%5C%5C%5C+%5Cdfrac%7B%5C%C2%BAC%7D%7B5%7D%3D+%5Cdfrac%7B50-32%7D%7B9%7D%5C%5C%5C%5C%5C%5C%5C+%5Cdfrac%7B%5C%C2%BAC%7D%7B5%7D%3D+%5Cdfrac%7B18%7D%7B9%7D%5C%5C%5C%5C%5C%5C%5C+%0A%5Cdfrac%7B%5C%C2%BAC%7D%7B5%7D%3D+2%5C%5C%5C%5C%5C%5C%0A%5C%C2%BAC%3D10%5C%C2%BA%5C%5C%5C%5C%5C%5C%5C%0A%5Cboxed%7BResposta%3ATemperatura%3D10%5C%C2%BAC%7D+ "\dfrac{\ºC}{5}= \dfrac{\ºF-32}{9}\\\\\\\ \ºF=50\º \\\\\\\ \dfrac{\ºC}{5}= \dfrac{50-32}{9}\\\\\\\ \dfrac{\ºC}{5}= \dfrac{18}{9}\\\\\\\
\dfrac{\ºC}{5}= 2\\\\\\
\ºC=10\º\\\\\\\
\boxed{Resposta:Temperatura=10\ºC}")
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