Question

a expressão dy/dx se x³+y³x²=2?

Answer 1

$x^3+y^3x^2=2\\\\3x^2+x^2(3y^2)y'+2xy^3=0\\\\3x^2+3x^2y^2y'+2xy^3=0\\\\y'=\dfrac{-3x^2-2xy^3}{3x^2y^2}=-\dfrac{3x-2y^3}{3xy^2}$