Question

a equação x2-3x=10 admite a: raiz -2, raiz -5 , raiz 2 , raiz 4

Answer 1

Oi

x² - 3x =10
x² -3x-10=0
Δ=b²-4.a.c
a=1
b=-3
c=-10

Δ=(-3)²-4.1.(-10)
Δ=9+40
Δ=49

x=$\frac{-b+- \sqrt{delta} }{2.a}$

x1=$\frac{+3+7}{2} = \frac{10}{2} =+5$


x"=$\frac{+3-7}{2} = \frac{-4}{2} = -2$

S( x'=+5 e x"=-2)

Bons estudos!!!

Answer 2

x2-3x=10
-4x=10-2
-4x=8
X=8/-4
X=-2