Question

a equacao (x-4).(x-10)=0 admite duas raizes cuja a soma e igual a 14?

Answer 1

(x-4)(x-10)
x²- 10x-4x+40=0
x² - 14x+ 40=0

a=1
b= -14
c= 40

Δ= b² - 4ac
Δ= -14² - 4*1*40
Δ= 196-160
Δ=36

x= -b +/- raiz de delta/2a
x= -(-14) +-  $\sqrt{36}$ /2
x=14+-6/2
x1=14+6 = 20/2 = 10
x2= 14-6 = 8/2 = 4


10+4= 14
SIM. A SOMA DAS DUAS RAIZES DÁ IGUAL A 14