Question

A equação (2p - 5)y^2 - (p + 2)y + 5 = 0 tem raiz y = 1. Qual é o valor de p?

Answer 1

(2p-5)y^2-(p+2)y+5=0                          
como y=1                                              
(2p-5)(1)^2-(p+2)(1)+5=0                    
(2p-5)1-(p+2)1+5=0                               
2p-5-p-2+5=0                                           
p-2=0                                                          
p=2