Question

a distancia entre os pares ordenados a 3,-1 e b 3,5 é​

Answer 1

Resposta: c) 6

Explicação passo-a-passo:

Olá,

* calculando:

A (3, -1) >> (x1, y1)

B (3, 5) >> (x2, y2)

dAB = √(x2 - x1)² + (y2 - y1)²

dAB = √(3 - 3)² + (5 - (-1))²

dAB = √(3 - 3)² + (5 + 1)²

dAB = √(0)² + (6)²

dAB = √0 + 36

dAB = √36

dAB = 6

bons estudos!

Answer 2

✅ tendo finalizado os cálculos, concluímos que o valor da distância entre os referidos pontos é:

  $\Large\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf d(A, B) = 6\:u.\:c.\:\:\:}}\end{gathered} }$

Sendo os pontos dados do plano cartesiano:

                 $\Large\begin{cases} A(3, -1)\\B(3, 5)\end{cases}$

Para calcular a distância entre os referidos pontos fazemos:

  $\Large\displaystyle\text{ \begin{gathered} d(A, B) = \sqrt{(X_{B} - X_{A})^{2} + (Y_{B} - Y_{A})^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{(3 - 3)^{2} + (5 - (-1))^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{0^{2} + (5 + 1)^{2}}\end{gathered} }$

                    $\Large\displaystyle\text{ \begin{gathered} = \sqrt{0^{2} + 6^{2}}\end{gathered} }$

                    $\Large\displaystyle\begin{gathered} = \sqrt{36}\end{gathered}$

                    $\Large\displaystyle\begin{gathered} = 6\end{gathered}$

✅ Portanto, a distância é:

   $\Large\displaystyle\begin{gathered} d(A, B) = 6\:u.\:c.\end{gathered}$

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered} }$

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$\Large\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Observe \:o\:Gr\acute{a}fico!!\:\:\:}}}\end{gathered} }$