a distancia do ponto A(a,1) ao ponto B(0,2) e igual a 3. calcule o valor da abscissa a
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Respondido por
6
Olá Carlos
dAB² = (Ax - Bx)² + (Ay - By)²
dAB² = (a - 0)² + (1 - 2)² = 3²
a² + 1 = 9
a² = 8
a1 = 2√2 e a2 = -2√2
dAB² = (Ax - Bx)² + (Ay - By)²
dAB² = (a - 0)² + (1 - 2)² = 3²
a² + 1 = 9
a² = 8
a1 = 2√2 e a2 = -2√2
Respondido por
5
Boa tarde!
Solução!
![\sqrt{(a-0)^{2}+(2-1) ^{2} } =3\\\\\\
(\sqrt{a^{2}+1 })^{2} =(3)^{2} \\\\\\
a^{2}+1=9\\\\
a^{2}=9-1\\\\
a^{2} =8\\\\\
a= \sqrt{8}\\\\
a=\pm2\sqrt{2}](https://tex.z-dn.net/?f=+%5Csqrt%7B%28a-0%29%5E%7B2%7D%2B%282-1%29+%5E%7B2%7D++%7D+%3D3%5C%5C%5C%5C%5C%5C%0A+%28%5Csqrt%7Ba%5E%7B2%7D%2B1+%7D%29%5E%7B2%7D++%3D%283%29%5E%7B2%7D+%5C%5C%5C%5C%5C%5C%0Aa%5E%7B2%7D%2B1%3D9%5C%5C%5C%5C%0Aa%5E%7B2%7D%3D9-1%5C%5C%5C%5C%0Aa%5E%7B2%7D+%3D8%5C%5C%5C%5C%5C%0Aa%3D+%5Csqrt%7B8%7D%5C%5C%5C%5C%0Aa%3D%5Cpm2%5Csqrt%7B2%7D+ "\sqrt{(a-0)^{2}+(2-1) ^{2} } =3\\\\\\
(\sqrt{a^{2}+1 })^{2} =(3)^{2} \\\\\\
a^{2}+1=9\\\\
a^{2}=9-1\\\\
a^{2} =8\\\\\
a= \sqrt{8}\\\\
a=\pm2\sqrt{2}")
Boa tarde!
Bons estudos!
Solução!
Boa tarde!
Bons estudos!
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