Question

A) determine o sen (ângulo b) B) determine o cos (ângulo b) C) determine a tg (ângulo b) D) qual o valor aproximado do ângulo b?

Answer 1

Resposta:

x² = 40² + 16² => x² = 1600 + 256 => x² = 1856 => x= 8$\sqrt{29}$

A) $sen b = \frac{16}{8\sqrt{29} } => sen b = \frac{2}{\sqrt{29} } . \frac{\sqrt{29} }{\sqrt{29} } = \frac{2\sqrt{29} }{29}$

B) $cosb = \frac{40}{8\sqrt{29} } => cosb= \frac{5}{\sqrt{29} } . \frac{\sqrt{29} }{\sqrt{29} } = \frac{5\sqrt{29} }{29}$

C) $tgb = \frac{16}{40} = \frac{2}{5}$

D) ângulo b ≅ 22º