Question

A derivada da função y:5e^x-3x²+2+ln(x+3) é:

Answer 1

$y = 5e^x-3x^2+2+ln(x+3)\\ \\ y' = 5e^x-3*2x^{2-1}+0+\frac{1}{x+3}\\ \\ \boxed{y' = 5e^x-6x+\frac{1}{x+3}}$

Answer 2

y = 5e^x - 3x² + 2 + ln(x+3)

y' 5e^x - 6x + 1/(x+3)