Question

A derivada da funçao h(x) = senx
A derivada da funçao t (x) = 1/x
A derivada da funçao u(x) = √x
A derivada da funçao v (x) = cosx

Answer 1

$t(x) = x^{-1} =\ \textgreater \ t' =(-1)x^{-2} = - \frac{1}{x^{2} }\\\\ u(x ) = \sqrt{x} =\ \textgreater \ u' = \frac{1}{2 \sqrt{x} } \\\\ v(x) = cosx =\ \textgreater \ v' = -senx$

Answer 2

$\sf h(x)=sen(x)\implies h'(x) =cos(x)\\\sf t(x)=\dfrac{1}{x}\implies t'(x)=-\dfrac{1}{x^2}\\\sf u(x)=\sqrt{x}\implies u'(x)=\dfrac{1}{2\sqrt{x}}\\\sf v(x)=cos(x)\implies v'(x)=-sen(x)$