a coordenadas do vértice da parábola de equação y=x-2x-3 e:
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Olá,
podemos identificar os termos da função quadrática acima..
O vértice da parábola é dado por:
![V=\left( -\dfrac{b}{2a},~- \dfrac{\Delta}{4a}\right)\\\\\\
V=\left\{-\left( \dfrac{-2}{2\cdot1}\right),~-\left[ \dfrac{(-2)^2-4\cdot1\cdot(-3)}{4\cdot1}\right]\right\}\\\\
V=\left\{-\left( \dfrac{-2}{~~2}\right),~-\left( \dfrac{4+12}{4}\right)\right\}\\\\
V=\left\{-(-1),~-\left( \dfrac{16}{4}\right)\right\}\\\\
\huge\boxed{\boxed{V=(1,-4)}}](https://tex.z-dn.net/?f=V%3D%5Cleft%28+-%5Cdfrac%7Bb%7D%7B2a%7D%2C%7E-+%5Cdfrac%7B%5CDelta%7D%7B4a%7D%5Cright%29%5C%5C%5C%5C%5C%5C%0AV%3D%5Cleft%5C%7B-%5Cleft%28+%5Cdfrac%7B-2%7D%7B2%5Ccdot1%7D%5Cright%29%2C%7E-%5Cleft%5B+%5Cdfrac%7B%28-2%29%5E2-4%5Ccdot1%5Ccdot%28-3%29%7D%7B4%5Ccdot1%7D%5Cright%5D%5Cright%5C%7D%5C%5C%5C%5C%0AV%3D%5Cleft%5C%7B-%5Cleft%28+%5Cdfrac%7B-2%7D%7B%7E%7E2%7D%5Cright%29%2C%7E-%5Cleft%28+%5Cdfrac%7B4%2B12%7D%7B4%7D%5Cright%29%5Cright%5C%7D%5C%5C%5C%5C%0AV%3D%5Cleft%5C%7B-%28-1%29%2C%7E-%5Cleft%28+%5Cdfrac%7B16%7D%7B4%7D%5Cright%29%5Cright%5C%7D%5C%5C%5C%5C%0A%5Chuge%5Cboxed%7B%5Cboxed%7BV%3D%281%2C-4%29%7D%7D+++++++ "V=\left( -\dfrac{b}{2a},~- \dfrac{\Delta}{4a}\right)\\\\\\
V=\left\{-\left( \dfrac{-2}{2\cdot1}\right),~-\left[ \dfrac{(-2)^2-4\cdot1\cdot(-3)}{4\cdot1}\right]\right\}\\\\
V=\left\{-\left( \dfrac{-2}{~~2}\right),~-\left( \dfrac{4+12}{4}\right)\right\}\\\\
V=\left\{-(-1),~-\left( \dfrac{16}{4}\right)\right\}\\\\
\huge\boxed{\boxed{V=(1,-4)}}")
Tenha ótimos estudos ;D
podemos identificar os termos da função quadrática acima..
O vértice da parábola é dado por:
Tenha ótimos estudos ;D
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