Question

A área da região hachurada vale:
(a) 3(π – 2)
(b) 2(8 – π)
(c) 4 – π
(d) 2(4 – π)
(e) 9 - π

Answer 1

Resposta:

π=3.14...

(a )3(π-2) = 3(3.14 - 2) = 3(1.14) = 3.4

(b) 2(8-π) = 2(8 - 3.14) = 2(4.86) = 9.7

(c) 4-π = 4 - 3.14 = 0.85

(d) 2(4 - π) = 2(4 - 3.14) = 2(0.85) = 1.7

(e) 9 - π = 9 - 3.14 = 5.8