Question

a area da chapa de prata mede 96cm2 a 80graus celcius calcule a area quando a temperatuta for 118graus celcius

Answer 1

$\boxed{\alpha_{Prata}=19\cdot10^{-6}}$

$\boxed{S'=2\alpha \cdot S_o \cdot \Delta \theta}$
$S'=2\alpha \cdot S_o \cdot (\theta_f-\theta_o)$
$S'=2 \cdot19\cdot10^{-6} \cdot 96 \cdot (118-80)$
$S'=2 \cdot19\cdot10^{-6} \cdot 96 \cdot 38$
$S'=38\cdot10^{-6} \cdot 3648$
$S'=138624\cdot10^{-6}cm^2$
$S'=0,138624cm^2$

$S_f=S'+S_o$
$S_f=0,138624+96$
$\boxed{S_f=96,138624cm^2}$