Question

A altura de um triângulo equilátero vale 6 raiz de 3 cm calcule o perímetro

Answer 1

$h= \dfrac{l \sqrt{3} }{2}\\\\\\\\ 6 \sqrt{3}= \dfrac{l \sqrt{3} }{2}\\\\\\\ (6 \sqrt{3})^2=(\dfrac{l \sqrt{3} }{2})^2\\\\\\\\36 \times 3= \dfrac{l^2 \times 3}{4}\\\\ 108= \dfrac{3l^2}{4}\\\\\\ 432=3l^2\\\\\\\\l^2= \dfrac{432}{3} \\\\\\l^2=144\\\\l= \sqrt{144} \\\\\\l=12$

Agora basta multiplicar por 3, já que o triângulo tem 3 lados

$P=3 \times L\\P=3 \times 12\\P=36\ cm$


Forte abraço!