Question

a) a²+4a+4

b)9x²+6xy+y²

Answer 1

a^2+4a+4=(a+2)^2

9x^2+6xy+y^2= (3x+y)^2

Answer 2

Trinômios quadrados perfeitos:

$\boxed{a^2\pm2ab+b^2=(a\pm b)^2}$

a)

$a^2+4a+2=a^2+2.2a+2^2=(a+2)^2$

b)

$9x^2+6xy+y^2=(3x)^2+2.3xy+y^2=(3x+y)^2$