Question

A+A+A=27/A+B+B=19/B.C-A=345, qual valor de C?​

Answer 1

A + A + A = 27 -> 3A = 27 -> A = 27/3 -> A = 9

A + B + B = 19 -> 9 + 2B = 19 -> 2B = 19 - 9 -> 2B = 10 -> B = 10/2 -> B = 5

B.C - A = 345 -> 5.C - 9 = 345 -> 5.C = 345 + 9 -> 5.C = 354 -> C = 354/5 -> C = 70,8