Question

a) (a + 7)² = b) (3x + 1)² = c) (5 + 2m)² = d) (a + 3x)² = e) (5x² + 1)² =​

Answer 1

Utilizarei o método da distributiva para facilitar

A

$(a + 7)(a + 7) = {a}^{2} + 7a + 7a + 49$

${a}^{2} + 14a + 49$

B

$(3x + 1)(3x + 1) = 9 {x}^{2} + 3x + 3x + 1$

$9 {x}^{2} + 6x + 1$

C

$(5 + 2m)(5 + 2m) = 25 + 10m + 10m + 4 {m}^{2}$

${4m}^{2} + 20m + 25$

D

$(3x + a)(3x + a) = {9x}^{2} + 3xa + 3xa + {a}^{2}$

${9x}^{2} + 6xa + {a}^{2}$

E

$( {5x}^{2} + 1)( {5x}^{2} + 1) = 25 {x}^{4} + 5 {x}^{2} + 5 {x}^{2} + 1$

${25x}^{4} + 10 {x}^{2} + 1$