Question

a ) (7x^2 y ) . ? = 14 x^3 y^2

b ) $\frac{?}{3xy} = \frac{2}{3}by$

c ) (-ab^2c) . ? = -ab^5 c

Answer 1

A)
(7.x².y).k = 14.x³y²
k = 14.x³y²/(7.x².y)
k = 2.x.y

B)
k/(3.x.y) = 2.b.y/3
3.k = (3.x.y).(2.b.y)
3.k = 6.b.x.y²
k = 6.b.x.y² / 3
k = 2.b.x.y²

C)
-(ab².c).k = -a.b⁵.c
k = -a.b⁵.c / -a.b².c
k = b³