Question

a = (6 elevado a 2 x 9 elevado a 5) elevado a -4

Answer 1

$([tex] 6^{2}$ x $9^{5}$ )^{-4} [/tex] =
=$6^{-8}$ x$9^{-20}$ =
=$2^{-8}$ x$3^{-8}$ x$3^{-40}$ =
=$2^{-8}$ x $3^{-48}$ =
=$\frac{1}{ 2^{8} }$ x $\frac{1}{ 3^{48} }$