a) 6 × {3 + [(9 × 3 - 22 ) + 2 ] }=
b) 62 - [ 10 + ( 2 × 8 - 6 ) + 5 ] =
c) 8 × [ 17 - ( 5 × 2 + 3 ) ] =
d) 76 - [12 + (4 × 4 -8 ) × 3]=
e) [49 - (6 × 6 - 15 - 15 ) + 7]=
Soluções para a tarefa
Respondido por
4
Olá, Larissa. (=^.^=)/
A) 6×{3+[(9×3-22)+2]} = 60
B) 62-[10+(2×8-6)+5] = 37
C) 8×[17-(5×2+3)] = 32
D) 76-[12+(4×4-8)×3] = 40
E) [49-(6×6-15-15)+7] = 50
A) 6×{3+[(9×3-22)+2]} =
6.{3+[(27-22)+2]} =
6.{3+[5+2]} =
6.{3+7} =
6.10 = 60
B) 62-[10+(2×8-6)+5] =
62-[10+(16-6)+5] =
62-[10+10+5] =
62-[25] =
62-25 = 37
C) 8×[17-(5×2+3)] =
8.[17-(10+3)] =
8.[17-(13)] =
8.[17-13] =
8.4 = 32
D) 76-[12+(4×4-8)×3] =
76-[12+(16-8).3] =
76-[12+8.3] =
76-[12+24] =
76-[36] =
76-36 = 40
E) [49-(6×6-15-15)+7] =
[49-(36-15-15)+7] =
[49-(36-30)+7] =
[49-(6)+7] =
[49-6+7] =
[56-6] = 50
Regras dos sinais:
+ com + = +
- com - = +
- com + = -
+ com - = -
Bons estudos! :-)
A) 6×{3+[(9×3-22)+2]} = 60
B) 62-[10+(2×8-6)+5] = 37
C) 8×[17-(5×2+3)] = 32
D) 76-[12+(4×4-8)×3] = 40
E) [49-(6×6-15-15)+7] = 50
A) 6×{3+[(9×3-22)+2]} =
6.{3+[(27-22)+2]} =
6.{3+[5+2]} =
6.{3+7} =
6.10 = 60
B) 62-[10+(2×8-6)+5] =
62-[10+(16-6)+5] =
62-[10+10+5] =
62-[25] =
62-25 = 37
C) 8×[17-(5×2+3)] =
8.[17-(10+3)] =
8.[17-(13)] =
8.[17-13] =
8.4 = 32
D) 76-[12+(4×4-8)×3] =
76-[12+(16-8).3] =
76-[12+8.3] =
76-[12+24] =
76-[36] =
76-36 = 40
E) [49-(6×6-15-15)+7] =
[49-(36-15-15)+7] =
[49-(36-30)+7] =
[49-(6)+7] =
[49-6+7] =
[56-6] = 50
Regras dos sinais:
+ com + = +
- com - = +
- com + = -
+ com - = -
Bons estudos! :-)
larissarodrigues13:
obg
Perguntas interessantes