Question

a) 5x(x-2)=4-(-2x+1)=

b)3+(x-4)=3(x-4)=

c)3-2(x+3)=x-18

Answer 1

A) 5x(x-2) = 4-(-2x+1)
5x² - 10 = 4 + 2x - 1
5x² - 2x - 10 - 3 = 0
5x² - 2x - 13 = 0
Δ = b² - 4ac = 4 - 4(5)(-13) = 4 + 260 = 264 = 2³ (33)
x = (-b ± √Δ) / 2a = 2 ± 2√66) / 10 =  (1 ± √66) / 5

b)3+(x-4)=3(x-4)
3 + x - 4 = 3x - 12
x - 1 = 3x - 12
x - 3x = -12 + 1
-2x = -11
x = 11/2

c)3-2(x+3)=x-18
3 - 2x - 6 = x - 18
-3 - 2x = x - 18
-2x - x = - 18 + 3
-3x = -15
x = -15/-3
x = 5